2-E IMPACT PHYSICS - Conservation of Momentum - LynnBlakeGolf Forums

2-E IMPACT PHYSICS - Conservation of Momentum

Chapter 2

 
 
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Old 04-27-2006, 08:35 AM
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Chapter 2E GM#170
Originally Posted by bobbywayne
Originally Posted by mb6606
Please explain "to do this the ball must be travelling 150 mph"
I have no idea what this line means when Homer is talking about seperation speed of 70% of 100 mph
thanks

Homer is saying that a golf ball will separate itself from the clubface at a speed that is approximately 70% of a high approach speed. However, that is separation speed, which means faster than it was already travelling.

So, assume a clubhead approaching at 100 mph. It impacts the ball, which causes the clubhead to slow to about 80 mph. For a short time, the ball travels along "stuck" to a clubface travelling 80 mph. The ball then "springs" off the clubface at a speed 70 mph faster than it was travelling while it was "stuck" to the clubface. 80 mph + 70 mph = 150 mph separation speed.

Correct, Bobbywayne. The Ball picks up 70 percent of Clubhead Approach Speed and 100 percent of Clubhead Separation Speed. Impact causes the Clubhead to slow considerably, and without active resistance to this deceleration, the Clubhead will slow even more. That is why it is so important -- Hitter or Swinger -- to keep driving through Impact!
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